Decision Science | Chapter 3 | Part 3 | MBA MCQs | DS
Decision Science MCQs
- The best use of linear programming technique is to find an optimal use of
- Money
- Manpower
- Machine
- All of the above
- Which of the following is not a characteristic of the LP
- Resources must be limited
- only one objective function
- Parameters value remains constant during the planning period
- The problem must be of minimization type
- Non-negativity condition in an LP model implies
- A positive coefficient of variables in objective function
- A positive coefficient of variables in any constraint
- Non-negative value of resources
- None of the above
- Which of the following is an assumption of an LP model
- Divisibility
- Proportionality
- Additivity
- All of the above
- Which of the following is a limitation associated with an LP model
- The relationship among decision variables in linear
- No guarantee to get integer valued solutions
- No consideration of effect of time & uncertainty on LP model
- All of the above
- The graphical method of LP problem uses
- Objective function equation
- Constraint equations
- Linear equations
- All of the above
- A feasible solution to an LP problem
- Must satisfy all of the problem’s constraints simultaneously
- Need not satisfy all of the constraints, only some of them
- Must be a corner point of the feasible region
- Must optimize the value of the objective function
- Which of the following statements is true with respect to the optimal solution of an LP problem
- Every LP problem has an optimal solution
- Optimal solution of an LP problem always occurs at an extreme point
- At optimal solution all resources are completely used
- If an optimal solution exists, there will always be at least one at a corner
- An iso-profit line represents
- An infinite number of solutions all of which yield the same profit
- An infinite number of solution all of which yield the same cost
- An infinite number of optimal solutions
- A boundary of the feasible region
- If an iso-profit line yielding the optimal solution coincides with a constaint line, then
- The solution is unbounded
- The solution is infeasible
- The constraint which coincides is redundant
- None of the above
- While plotting constraints on a graph paper, terminal points on both the axes are connected by a straight line because
- The resources are limited in supply
- The objective function as a linear function
- The constraints are linear equations or inequalities
- All of the above
- A constraint in an LP model becomes redundant because
- Two iso-profit line may be parallel to each other
- The solution is unbounded
- This constraint is not satisfied by the solution values
- None of the above
- If two constraints do not intersect in the positive quadrant of the graph, then
- The problem is infeasible
- The solution is unbounded
- One of the constraints is redundant
- None of the above
- Constraints in LP problem are called active if they
- Represent optimal solution
- At optimality do not consume all the available resources
- Both a & b
- None of the above
- The solution space (region) of an LP problem is unbounded due to
- An incorrect formulation of the LP model
- Objective function is unbounded
- Neither a nor b
- Both a & b
- While solving a LP model graphically, the area bounded by the constraints is called
- Feasible region
- Infeasible region
- Unbounded solution
- None of the above
- Alternative solutions exist of an LP model when
- One of the constraints is redundant
- Objective function equation is parallel to one of the constraints
- Two constraints are parallel
- All of the above
- While solving a LP problem, infeasibility may be removed by
- Adding another constraint
- Adding another variable
- Removing a constraint
- Removing a variable
- If a non-redundant constraint is removed from an LP problem then
- Feasible region will become larger
- Feasible region will become smaller
- Solution will become infeasible
- None of the above
- If one of the constraint of an equation in an LP problem has an unbounded solution,
then- Solution to such LP problem must be degenerate
- Feasible region should have a line segment
- Alternative solutions exist
- None of the above
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